【問題】請各位這條題目為何答案是b?

[mok2000]

請各位這條題目為何答案是b?????????????????


You are creating a DHCP scope for your 192.168.1.32/28 subnet. The
subnet consists of Windows 2000, Windows 98, and Windows 95 computers.

You have two UNIX computers on this subnet that will be assigned the two
highest available static IP addresses. The subnet's default gateway will
be assigned the lowest available IP address on the subnet.

Which scope should you create on your DHCP server?

A. 192.168.1.34 - 192.168.1.46
B. 192.168.1.34 - 192.168.1.44
C. 192.168.1.33 - 192.168.1.45
D. 192.168.1.34 - 192.168.1.61
E. 192.168.1.33 - 192.168.1.60

Answer: B

[tahoo]

最初由 mok2000 發表
請各位這條題目為何答案是b?????????????????


You are creating a DHCP scope for your 192.168.1.32/28 subnet. The
subnet consists of Windows 2000, Windows 98, and Windows 95 computers.

You have two UNIX computers on this subnet that will be assigned the two
highest available static IP addresses. The subnet's default gateway will
be assigned the lowest available IP address on the subnet.

Which scope should you create on your DHCP server?

A. 192.168.1.34 - 192.168.1.46
B. 192.168.1.34 - 192.168.1.44
C. 192.168.1.33 - 192.168.1.45
D. 192.168.1.34 - 192.168.1.61
E. 192.168.1.33 - 192.168.1.60

Answer: B

以下的解釋夠清楚了吧
192.168.1.32 (Subnet Address)
192.168.1.33 (Lowest avaliable IP) Reserved for Gateway
192.168.1.34-44 (avaliable scope IP)
192.168.1.45-46 (highest 2 IP) Reserved for Unix machines
192.168.1.47 (Broadcast address)

[winson39]

[QUOTE]最初由 mok2000 發表
[B]請各位這條題目為何答案是b?????????????????


You are creating a DHCP scope for your 192.168.1.32/28 subnet. The
subnet consists of Windows 2000, Windows 98, and Windows 95 computers.

You have two UNIX computers on this subnet that will be assigned the two
highest available static IP addresses. The subnet's default gateway will
be assigned the lowest available IP address on the subnet.

Which scope should you create on your DHCP server?

A. 192.168.1.34 - 192.168.1.46
B. 192.168.1.34 - 192.168.1.44
C. 192.168.1.33 - 192.168.1.45
D. 192.168.1.34 - 192.168.1.61
E. 192.168.1.33 - 192.168.1.60

Answer: B
由192.168.1.32/28 得知各網段的ip分配如下
0~15
16~31
32~47
48~63
以上均需去掉頭尾的ip,理由應該知道
subnet mask 為255.255.255.240
架設dhcp(ip需固定), 但二台unix需要固定ip
共需要3個固定ip
A. 192.168.1.34 - 192.168.1.46 (網段符合,但沒有只留一個ip)
B. 192.168.1.34 - 192.168.1.44 (網段符合,33應為dhcp-server且留了45.46二個ip給unux
C. 192.168.1.33 - 192.168.1.45 (網段符合,但留的ip只有二個,加上dhcp應要留３個）
D. 192.168.1.34 - 192.168.1.61 （網段不符）
E. 192.168.1.33 - 192.168.1.60 （網段不符）


以上如有錯誤請指正

[mok2000]

多謝大家指點